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报错：No identifier specified for entity: main.java.com.sy.entity.User的解决办法

自己也没怎么搭建过框架，更何况还是 spring mvc 的，最近在带两个实习生，正好教他们怎么搭建一个 spring mvc 的框架，然而我在映射表的时候，提示报错了。

 

实体基类：

public class BaseEntity implements Serializable{

@Id
@GeneratedValue(strategy </span>=<span style="color: rgba(0, 0, 0, 1)"> GenerationType.AUTO)
</span><span style="color: rgba(0, 0, 255, 1)">protected</span><span style="color: rgba(0, 0, 0, 1)"> Long id;

@Column(updatable</span>=<span style="color: rgba(0, 0, 255, 1)">false</span><span style="color: rgba(0, 0, 0, 1)">)
</span><span style="color: rgba(0, 0, 255, 1)">protected</span> Date creatTime=<span style="color: rgba(0, 0, 255, 1)">new</span><span style="color: rgba(0, 0, 0, 1)"> Date();

@Column(updatable</span>=<span style="color: rgba(0, 0, 255, 1)">false</span><span style="color: rgba(0, 0, 0, 1)">)
</span><span style="color: rgba(0, 0, 255, 1)">protected</span><span style="color: rgba(0, 0, 0, 1)"> String creatUser;

@Column(insertable</span>=<span style="color: rgba(0, 0, 255, 1)">false</span><span style="color: rgba(0, 0, 0, 1)">)
</span><span style="color: rgba(0, 0, 255, 1)">protected</span> Date updateTime=<span style="color: rgba(0, 0, 255, 1)">new</span><span style="color: rgba(0, 0, 0, 1)"> Date();

@Column(insertable</span>=<span style="color: rgba(0, 0, 255, 1)">false</span><span style="color: rgba(0, 0, 0, 1)">)
</span><span style="color: rgba(0, 0, 255, 1)">protected</span><span style="color: rgba(0, 0, 0, 1)"> String updateUser;

</span><span style="color: rgba(0, 128, 0, 1)">//</span><span style="color: rgba(0, 128, 0, 1)">get,set方法</span>



}

 

User 类：

@Entity
@Table(name="sys_user")
public class User extends BaseEntity {

</span><span style="color: rgba(0, 0, 255, 1)">private</span><span style="color: rgba(0, 0, 0, 1)"> String loginName;

</span><span style="color: rgba(0, 0, 255, 1)">private</span><span style="color: rgba(0, 0, 0, 1)"> String userName;

</span><span style="color: rgba(0, 0, 255, 1)">private</span><span style="color: rgba(0, 0, 0, 1)"> String password;

</span><span style="color: rgba(0, 128, 0, 1)">//</span><span style="color: rgba(0, 128, 0, 1)">get、set方法</span>


    
}

 

代码看了感觉没问题啊，查阅国外的论坛之后得出一个结论，自己好菜啊！解决办法特别简单！！！在实体基类上加一个@MappedSuperclass

@MappedSuperclass
public class BaseEntity implements Serializable{

@Id
@GeneratedValue(strategy </span>=<span style="color: rgba(0, 0, 0, 1)"> GenerationType.AUTO)
</span><span style="color: rgba(0, 0, 255, 1)">protected</span><span style="color: rgba(0, 0, 0, 1)"> Long id;

@Column(updatable</span>=<span style="color: rgba(0, 0, 255, 1)">false</span><span style="color: rgba(0, 0, 0, 1)">)
</span><span style="color: rgba(0, 0, 255, 1)">protected</span> Date creatTime=<span style="color: rgba(0, 0, 255, 1)">new</span><span style="color: rgba(0, 0, 0, 1)"> Date();

@Column(updatable</span>=<span style="color: rgba(0, 0, 255, 1)">false</span><span style="color: rgba(0, 0, 0, 1)">)
</span><span style="color: rgba(0, 0, 255, 1)">protected</span><span style="color: rgba(0, 0, 0, 1)"> String creatUser;

@Column(insertable</span>=<span style="color: rgba(0, 0, 255, 1)">false</span><span style="color: rgba(0, 0, 0, 1)">)
</span><span style="color: rgba(0, 0, 255, 1)">protected</span> Date updateTime=<span style="color: rgba(0, 0, 255, 1)">new</span><span style="color: rgba(0, 0, 0, 1)"> Date();

@Column(insertable</span>=<span style="color: rgba(0, 0, 255, 1)">false</span><span style="color: rgba(0, 0, 0, 1)">)
</span><span style="color: rgba(0, 0, 255, 1)">protected</span><span style="color: rgba(0, 0, 0, 1)"> String updateUser;

</span><span style="color: rgba(0, 128, 0, 1)">//</span><span style="color: rgba(0, 128, 0, 1)">get,set方法</span>



}